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4 years ago

Can i uninstall adobe lightroom 6 and reinstall

1 answer:

8 0

Try transferring it onto a flash drive. Remove from computer, restart computer, and plug in. Its like a baby hard reset. It lets the app completely reset while keeping all the data as well as the computer clearing its cache.

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Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme

Tasya [4]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

void PrintBackward(int myarray[], int size){

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

int main(){

const int ARRAY_SIZE = 12;

int multiplier;

cout<<"Multiplier: ";

cin>>multiplier;

int myarray [ARRAY_SIZE];

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

PrintForward(myarray,ARRAY_SIZE);

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

The main begins here

int main(){

This declares and initializes the array size

const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

int multiplier;

This gets input for the multiplier

cout<<"Multiplier: "; cin>>multiplier;

This declares the array

int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

This calls the PrintForward method

PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

6 0

3 years ago

Your Windows PC has an AMD processor installed that includes AMD-V technology and the motherboard fully supports this processor.

Anvisha [2.4K]

Answer:

Option C: Windows Virtual PC is the correct answer.

Explanation:

The virtualization program for Microsoft Windows is given by Windows Virtual PC. As discussed it has an AMD processor installed that includes AMD-V technology and the motherboard fully supports this processor.

The superseded version of Windows virtual PC is Hyper-V. It is the most capable version of Microsoft hypervisor you can install on this machine, provided the computer meets all the other requirements.

All other options are wrong as the virtualbox is not considered as the Microsoft hypervisor therefore can't be installed. Similarily, the hypervisor named as Windows XP mode is not so capable that it could meet all requirements. In the end, the Parallel Desktops can not be run on the machines as they dont come under the Microsoft hypervisor category.

I hope it will help you!

7 0

3 years ago

g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err

grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

// variables declared

int n;

int sum=0;

float avg;

{

// user input taken for number

cout<< "Enter a number between 1 and 100 (inclusive): ";

cin>>n;

if(n<1 || n>100)

cout<<" Number is out of range. Enter valid number."<<endl;

}while(n<1 || n>100);

cout<<" "<<endl;

// printing even numbers between num and 50

for(int num=1; num<=n; num++)

{

sum = sum + num;

}

avg = sum/n;

// displaying sum and average

cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

cout<<"Average of numbers between 1 and "<<n<<" is ";

printf("%.2f", avg);

return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0

3 years ago

The max-age attribute of a cookie is specified in

defon

Answer:

seconds.

Explanation:

max-age attribute of a cookie is specified in seconds.It sets the time when the cookie will be deleted.max-age attribute is not supported by all the browser.Internet Explorer does not support max-age.Son expires is used more than max-age because it supports almost all the browsers.

6 0

3 years ago

We can draw crescent using ?

Anarel [89]

Answer:

I think it's B

hope this helps

have a good day :)

Explanation:

4 0

3 years ago

Read 2 more answers