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Troyanec [42]
3 years ago
9

A rectangle is 2/5 in. long and 1/3 in. wide. What is the area of the rectangle?

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0
The area of the rectangle is 1/3 * 2/5=2/15 inches
please mark as brainliest
Len [333]3 years ago
4 0
If you mean 2,5 inch long and 1,3 inch wide the answer is 3,25 square inches.
Because the area of rectangle is a*b.
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If g(x)is the inverse of f(x)andf(x)=4x+12,what is g(x)?
ch4aika [34]
To find the inverse of a function, stick a y for the f(x).

So, f(x) = 4x + 12 becomes y = 4x + 12

Then switch the x and y.

So, y = 4x + 12 becomes x = 4y + 12

Then solve for y.

x = 4y + 12
x - 4y = 12 <-- Subtract both sides by 4y
-4y = 12 - x <-- Subtract both sides by x

y = -3 + \frac{x}{4}

So, the inverse of f(x) is g(x) = -3 + x/4.
8 0
2 years ago
Let e be the line through A (-4,5) and B (3. t) that is perpendicular to the line through
grigory [225]

Answer:

Step-by-step explanation:

product of slopes of perpendicular lines=-1

(t-5)/(3+4)×(2-3)/(-4-1)=-1

(t-5)/7×(-1/-5)=-1

(t-5)/35=-1

t-5=-1×35=-35

t=-35+5

t=-30

2.

slopes of parallel lines are equal.

(-2+3)/(t-4)=(-1-4)/(4+2)

1/(t-4)=-5/6

t-4=-6/5

t=4-6/5=(20-6)/5=14/5

3.

x>0,y<0

so P lies in4th quadrant.

except cos and sec all are negative.

so only cos and sec are positive.

8 0
3 years ago
Which of the following is the midsegment for A ACE?
11111nata11111 [884]

Answer:

A. DB

Step-by-step explanation:

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5 0
3 years ago
List all sets that apply for 0.6
uranmaximum [27]

Answer:

i know

Step-by-step explanation:0.6

3 0
3 years ago
A spherical exercise ball has a maximum diameter of 30 inches when filled with air. The ball was completely empty at the start,
Alex73 [517]

Answer:

A) A(t)  =  4500*π  -  1600*t

B) A(4)  =  7730 in³

C) t  =  8,8 sec

Step-by-step explanation:

The volume of the sphere is:

d max  =  30   r max  =  15 in

V(s) =  (4/3)*π*r³      V(s)  =   (4/3)*π* (15)³

V(s) = 4500*π

A)  Amount of air needed to fill the ball A(t)

A(t)  = Total max. volume of the sphere - rate of flux of air * time

A(t)  =  4500*π  -  1600*t    in³

B) After 4 minutes

A(4)  =  4500*π  - 6400

A(4)  =  14130 - 6400

A(4)  =  7730 in³

C)  A(t)  =  4500*π  -  1600*t  

when  A(t) = 0   the ball got its maximum volume then:

4500*π -  1600*t  =  0

t  =   14130/1600

t  =  8,8 sec

8 0
2 years ago
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