Complete Question
ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.
a. What is the value of the sample test statistic? (Round your answer to two decimal places.)
b. Find the P-value of the test statistic. (Round your answer to four decimal places.)
Answer:
a) 
b) 
Step-by-step explanation:
From the question we are told that:
Probability of Wishart and Leach 
Population Size 
Sample size 
Therefore


Generally the Null and Alternative Hypothesis is mathematically given by


Test Statistics



Therefore P Value is given as




Answer:
Interest= $ 18.73
Step-by-step explanation:
Given : $600 at 9.5% for 120 days
To find : Find the interest due
Solution :
Simple interest formula 
Principle(P)=$600 , rate(r)=9.5%=0.095 , time (t)= 120 days
In years, 1 year = 365 days
1 day =
year
120 days =
year
Put values in the formula


Therefore, Interest= $ 18.73
The simplified expression of 2√8x³(3√10x⁴ - x√5x²) is 24x³√5x - 4x³√10x
<h3>How to determine the simplified product?</h3>
The complete question is added as an attachment
From the attached figure, the product expression is:
2√8x³(3√10x⁴ - x√5x²)
Evaluate the exponents
2√8x³(3√10x⁴ - x√5x²) = 2 *2x√2x(3x²√10 - x²√5)
Evaluate the products
2√8x³(3√10x⁴ - x√5x²) = 4x√2x(3x²√10 - x²√5)
Open the bracket
2√8x³(3√10x⁴ - x√5x²) = 12x³√20x - 4x³√10x
Evaluate the exponents
2√8x³(3√10x⁴ - x√5x²) = 24x³√5x - 4x³√10x
Hence, the simplified expression of 2√8x³(3√10x⁴ - x√5x²) is 24x³√5x - 4x³√10x
Read more about expressions at:
brainly.com/question/12990602
#SPJ1
Answer:
→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>
→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>
→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>
Step-by-step explanation:
• let numbers be x, y and z

• from eqn 2, make x the subject:

• substitute all variables in eqn 3:

• find z

• find x:

Rounding to nearest value:
