To make two batches of nut bars jayda needs to use 4eggs. How many eggs are used in each batch of nut bars?

−5x+2y=9<br> y=7x<br> x=<br> y=

Serhud [2]

$- 5x+2y=9 \\ y=7x$

We know that y=7x, so we just need tu put it into the 1st equation

$- 5x + 2 \times 7x = 9 \\ - 5x + 14x = 9 \\ 9x = 9 | \div 9 \\ 9x \div 9 = 9 \div 9 \\ x = 1$

So we found x. Now we can find y

$y = 7 \times 1 \\ y = 7$

Answer:

x=1, y=7; or (1;7)

4 0

3 years ago

A set of computer science exam scores are normally distributed with a mean of 71.33 point, and a standard deviation of 3 points.

Bess [88]

Answer: 0.86 of the exam scores are between 68 and 77.99 points

Step-by-step explanation:

Since the set of computer science exam scores are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = computer science exam scores .

µ = mean score

σ = standard deviation

From the information given,

µ = 71.33 points

σ = 3 points

We want to find the proportion of the exam scores are between 68 and 77.99 points. It is expressed as

P(68 ≤ x ≤ 77.99)

For x = 68,

z = (68 - 71.33)/3 = - 1.11

Looking at the normal distribution table, the probability corresponding to the z score is 0.13

For x = 68,

z = (77.99 - 71.33)/3 = 2.22

Looking at the normal distribution table, the probability corresponding to the z score is 0.99

P(68 ≤ x ≤ 77.99) = 0.99 - 0.13 = 0.86

5 0

3 years ago

A customer service phone line claims that the wait times before a call is answered by a service representative is less than 3.3

8_murik_8 [283]

Answer:

Step-by-step explanation:

Let x be the wait times before a call is answered in phone calls.

The claim is x bar <3.3 minutes

Sample size n =62

Sample mean - x bar = 3.24 minutes

Population std dev = $\sigma = 0.40 minutes\\$

Since population std dev is known and also sample size is sufficiently large, we can use Z test.

$H_0: x bar = 3.3\\H_a: x bar$

(one tailed test)

Mean difference = 3.24-3.3 = -0.06 min

Std error of sample = $\frac{\sigma}{\sqrt{n} } =\frac{0.40}{\sqrt{62} } \\=0.0508$

Z = tset statistic = $\frac{-006}{0.0508} \\\\=-1.18$

p value = 0.119

Since p value > alpha, we accept null hypothesis.

There is no evidence to support the claim at alpha = 0.08

3 0

3 years ago

Given the equation (x+a)^2(x-2)=x^3+bx^2+12x-72 find a and b

GaryK [48]

Isolate the variable by dividing each side by factors that don't contain the variable.

$a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}$

Solve for b by simplifying both sides of the equation then isolating the variabel.

$b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }$

Hopefully i helped ^.^ Mark brainly if possible

7 0

3 years ago

This is mathematics ratios can u help me pls

ExtremeBDS [4]

I hope this helps you, let me know if you need more clarification. Also, it's supposed to say apples are $0.70 per pound.

8 0

4 years ago