The answer for this problem

A video game arcade offers a yearly membership with reduced rates for game play. A single membership costs $60 per year. Game to

Nastasia [14]

Let

x-------> the number of game tokens purchased for a member of the arcade

y-------> the function of the yearly cost in dollars

we know that

the function y of the yearly cost in dollars is equal to

$y =\frac{1}{10} x +60$

This is the equation of the line

using a graph tool

see the attached figure

Statements

case a) The slope of the function is $1.00

The statement is False

The slope of the function is equal to $\frac{1}{10} \frac{\$}{tokens}$

case b) The y-intercept of the function is $60

The statement is True

we know that

The y-intercept of the function is the value of the function when the value of x is equal to zero

so

for $x=0$

$y =\frac{1}{10}*0 +60$

$y =\$60$

case c) The function can be represented by the equation y =(1/10)x + 60

The statement is True

The equation of the function is equal to $y =\frac{1}{10} x +60$

case d) The domain is all real numbers

The statement is False

The value of x cannot be negative, therefore the domain is the interval

[0,∞)

case e) The range is {y| y ≥ 60}

The statement is True

The range of the function is the interval-------> [60,∞)

see the attached figure

8 0

3 years ago

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What is the area of this figure?? PLEASE HELP

diamong [38]

Answer:

1410ft²

Step-by-step explanation:

20 * 12 * 2 + [62 * (15 + 12)] =

480 + (62 * 15) =

480 + 930 =

1410ft²

8 0

2 years ago

William sold half of his comic books and then bought 14 more he now has 24 with how many did he have in the beginning

Lera25 [3.4K]

Let the number of comic books be X
if we add 14 to X = 24
so we will find the value of X to get half initial number of comic books William had.
14+X=24
X=24-14
X=10
so the total innitial number of comic books William had is 10+10=20 books.

3 0

3 years ago

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PLZ HELP I DONT UNDERSTAND A password for a security system must consist of a eater followed by two digits. How many possible pa

Talja [164]

Answer:

7020

Step-by-step explanation:

The letter could be any 1 of the 26 and it could be placed in any 1 of 3 places so this makes 26*3 = 78 possibilities.

For each of these there is any one of permutations of 2 digits from 10

= 10P2 = 10! / 8! = 10*9 = 90.

So the answer is 78 * 90 = 7020.

Note I am assuming that the 2 digits picked are different - no duplicates.

please mark me brainliest!

4 0

3 years ago

What is the simplified form of the following expression? Assume y=0 ^3 sqrt 12x^2/16y

pochemuha

For this case we must simplify the following expression:

$\sqrt [3] {\frac {12x ^ 2} {16y}}$

We rewrite the expression as:

$\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=$

We multiply the numerator and denominator by:

$(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=$

We use the rule of power $a ^ n * a ^ m = a ^ {n + m}$ in the denominator:

$\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=$

Move the exponent within the radical:

$\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=$

$\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=$

$\frac{\sqrt[3]{6x^2*y^2}}{2y}$

Answer:

$\frac{\sqrt[3]{6x^2*y^2}}{2y}$

7 0

3 years ago

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