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kobusy [5.1K]
3 years ago
9

D=9.6mmcalculate the circumference ​

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0

Answer:

30.14

Step-by-step explanation:

  • The formula for cirumference is 2(pi)r
  • If the diameter equals 9.6 then the radius is 4.8
  • 4.8 times 2 equals 9.6
  • 9.6 times 3.14(pi) equals 30.144 which could be rounded to 30.14
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Evaluate (-3^-3)\6^-2. Write your answer as a fraction in simplest form.​
Vanyuwa [196]

- 4 / 3 is the answer, just simplify

6 0
2 years ago
Consider the functions f(x) = 3x2, g(x)=1/3x , and h(x) = 3x. Which statements accurately compare the domain and range of the fu
Genrish500 [490]

Answer:

all of the functions have a unique range ⇒ answer 1

Step-by-step explanation:

* Lets revise how to find the domain and the range of the function

- The domain is all values of x that make the function defined

- The range is the set of all output values of a function

∵ f(x) = 3x²

- It is a quadratic function

- There is no values of x make this function undefined

∴ The domain of f(x) is all real numbers

- To find the range calculate the vertex of the function

∵ f(x) = ax² + bx + c

∵ f(x) = 3x²

∴ a = 3 , b = 0 , c = 0

∵ h = -b/2a

∴ h = 0/2(3) = 0/6 = 0

∵ k = f(h)

∴ k = f(0) = 3(0)² = 0

∴ The vertex of the cure is (0 , 0)

∵ k is the minimum value of the parabola

∴ The range of f(x) is all real numbers greater than or equal

  to zero ⇒ (1)

∵ g(x) = 1/3x

- It is a rational function

- to find the values of x which make the function undefined equate

 the denominator by 0

∵ 3x = 0 ⇒ divide both sides by 0

∴ x = 0

∴ The domain of g(x) is all real numbers except zero

∵ We can not put x = 0, then there is no value of g(x) at x = 0

∴ The range of the g(x) is all real number except zero ⇒ (2)

∵ h(x) = 3x

- It is a linear function

∵ There is no values of x make this function undefined

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is all real numbers ⇒ (3)

* From (1) , (2) , (3) the answer is

 all of the functions have a unique range

# Look to the attached graph to more understand

The red graph is f(x)

The blue graph is g(x)

The green graph is h(x)

8 0
3 years ago
Read 2 more answers
Jennifer hit a golf ball from the ground and it followed the projectile ℎ(t)= −15t^2+100t, where t is the time in seconds, and ℎ
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

In order to find the max height the ball reached, we have to complete the square on that quadratic. That will also, conveniently so, give us the number of seconds it will take the ball to reach that max height, that answer to part b. Let's begin to complete the square. Normally, you would move the constant over to the other side of the equals sign, but there is no constant here. The next step is to get the leading coefficient to be a 1, and ours right now is a -15. So we have to factor it out. Here's where we start the process of completing the square.

-15(t^2-\frac{20}{3}t)=0 Next step is to take half the linear term, square it, and add it to both sides. Our linear term is 20/3. Half of 20/3 is 20/6, and 20/6 squared is 400/36.

-15(t^2-\frac{20}{3}t+\frac{400}{36})=0+??? Because this is an equation, what we add to the left side also has to be added to the right. BUT we didn't just add in 400/36, because we have that -15 out front as a multiplier that refuses to be ignored. What we actually added in was -15(400/36):

-15(t^2-\frac{20}{3}t+\frac{400}{36})=0-\frac{500}{3}

The reason we do this is to create a perfect square binomial on the left which will serve as the number of seconds, h, in the vertex (h, k), where h is the number of seconds it takes the ball to reach its max height, k. Simplifying both sides then gives us:

-15(t-\frac{20}{6})^2=-\frac{500}{3} Finally, we will move the right side over by the left and set the quadratic back equal to h(t):

h(t)=-15(t^2-\frac{20}{3})^2+\frac{500}{3} and from that you can determine that the vertex is (\frac{20}{3},\frac{500}{3}).

The answer to a. is vound in the second number of our vertex: k, the max height. The max of the golf ball was 500/3 feet or 166 2/3 feet.

Part b is found in the first number of the vertex: h, the number of seconds it took the golf ball to reach that max height. The time it took was 3 1/3 seconds.

Part c. is to state the domain (the time) and the range (the height) of the ball.

Domain is

D: {x | 0 ≤ x ≤ 3 1/3} and

Range is

R: {y | 0 ≤ y ≤ 166 2/3}

8 0
3 years ago
What is the vertex of the graph of the function below ?<br> y=x^2-4x+3
VARVARA [1.3K]
Your vertex is (2, - 1)
4 0
3 years ago
The quotient of a number and 3 decreased by 121 is -164. Select the solution to the sentence shown.
docker41 [41]
Its algebra. The original equation is \frac{x}{3} -121 = -164

To solve for a variable, we reverse the order of operations, beginning with addition/subtraction, and then multiplication/division. To remove a number from one side, we must do the opposite to the other side. In this case, to get rid of the -121 we must add 121 to the -164. This gives us -43. Then, to get the x by itself, we must multiply the other side by 3. -43*3=129

When we are doing the opposite of an operation to the other side, we are really reversing the operation and, to keep both sides equal, we must do whatever we have done to one side to the other side. So when we have -121, we add 121 as it equals 0, therefore it is gone. Since a equation must be balanced, we have to do what we did to the other side (adding 121).



6 0
3 years ago
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