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lutik1710 [3]
3 years ago
6

What is the answer to 11-2r+3=4

Mathematics
2 answers:
Mashcka [7]3 years ago
7 0
Using algebra, I obtained that r=5
wolverine [178]3 years ago
4 0
11-2r+3=4 first subtract 11 and 3 from both sides of the equation, so the equation looks like this:

-2r=-10 next, divide both sides by -2

r=5.
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Solve for h: v = pi squared multiplied by h h = V multiplied by pi over r squared h = V over pi r squared h = V plus pi r square
alexandr1967 [171]

Hello from MrBillDoesMath

Answer:

See below for steps.

Discussion:

As I understand the problem statement we have a cylinder of height h and radius r. The volume of the cylinder is given by the formaul:

V = (pi * r^2) h

Divide both sides by (pi * r^2):

V\ (pi * r^2)) =     ( (pi * r^2) * h ) \ ((pi * r^2)   =>

V\ (pi * r^2)  = 1 * h = h  as  (pi * r^2)   \ (pi * r^2))

Therefore, h =  V\ (pi * r^2)



Thank you,

Mr. B


7 0
3 years ago
Read 2 more answers
Simplify: –3y 2x – 10y – 5x 2y <br> a. –11y – 3x <br> b. –15y 3x <br> c. –15y – 3x <br> d. –11y 7x
hoa [83]
The answer is A.<span>–11y – 3x</span>
5 0
3 years ago
Type the integer that makes the following subtraction sentence true:<br> -57 - ? = -151
posledela

Answer:

94

Step-by-step explanation:

Its pretty simple,

The easiest way to find the missing number is to do 151-57, which = 94

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Determine which equation is belongs to the graph of the limacon curve below.
JulsSmile [24]

Answer: Option C.

Step-by-step explanation:

We have functions of r(θ)

In our graph, we can see that the minimum value of r is when θ = 0°, and the maximum value is when θ = 180°.

We also know that the graph is in the square (-5, 5)x(-5, 5) and you can see that the maximum radius is almost less than 5.

Then let's analyze the options:

A) r = 3 - 2*cos(θ)

the maximum is at the right angle, but the maximum is:

r = 3 -2*(-1) = 5, so this maximum value is bigger than the one in the graph.

B) r = 3 - sin(θ)

For the sin functions, the maximum and minimum do not correspond with the values i write earlier, so we can discard this option.

C) r = 3 - cos(θ)

The maximum is: r = 3 - (-1) = 4, so this may be the correct answer.

the minimum is r = 3 - 1 = 2,

this is a possible equation for our circle.

D) r = 2 - 2*cos(θ)

Here, when θ = 0, we have: r = 2 - 2*1 = 0, but in the graph we can see that the radius is not 0 when θ = 0, so we can discard this option.

So the only option that makes sense is option C.

8 0
3 years ago
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