Izaiaih would only be spending $309.75 since it was 35% off
6a-2 (a-1) in simplest form is 4a+2.
The answer is 10^4 x 4^5.
You just have to subtract the powers for the term with 4 as it’s base.
<span>Alright, here's your answer.
y-intercept is computed (not found) by assigning x = 0 and computing y: here that is f(0) = Log(2*0 + 1) – 1 = Log(1) – 1 = 0 – 1 = -1
y-intercept is (0, -1)
x-intercept is computed by solving f(x) = 0 for x: here that is
0 = Log(2x + 1) – 1 → 1 = Log(2x + 1)
Assuming the Log cited is base 10, then 10^1 = 10^Log(2x + 1) = 2x + 1
That’s 10 = 2x + 1
Therefore 9 = 2x
x = 9/2 = 4.5
Check this result in the original equation, I did!
Your answer is - x-intercept is (4.5, 0)
I hope I helped! :)
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<span>Let the distance of the point be P. From the question, the distance, P, is square root of the sum of the coordinates (x, y); so we have (X^2, Y^2) From the origin we have (0, 0) From elementary mathematics, distance of a point is . âš(X2 -X1)^2 - (Y2 - Y1)^2
So basically this is just the difference of the squares at varying points of X and Y.
At the origin, X1 = 0 and Y1 = 0 and so our equation reduces to âš(X2-0)^2 + (Y2 -0)^2. This becomes P =âšX^2 + Y^2</span>