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2 years ago

Point V is on line segment UW. Given VW = x, UV = 3x – 1, and

Mathematics

1 answer:

creativ13 [48]2 years ago

6 0

Answer:

4 units

Step-by-step explanation:

Since V lies on UW,

UV + VW = UW

$3x - 1 + x = 5x - 5 \\ 5x - x - 3x = 5 - 1 \\ x = 4$

Therefore, VW = 4 units

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Which of the following best describes a bisector of an angle? A. The set of all points included between two sides of a given ang

Illusion [34]

That would be B.

The set of points are all on the line which is a bisector.

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3 years ago

Read 2 more answers

A quadratic function that has the vertex (-2, -4) and passes through the point (-1, -6)

spayn [35]

Answer:

f(x) = -2 (x + 2)² - 4

Step-by-step explanation:

f(x) = a (x - h)² + k (h , k) is vertex h = -2 k = -4

pass point (-1 , -6) f(x) = -6 and x = -1

-6 = a (-1 - (-2))² + (-4)

-6 = a - 4

a = -2

quadratic function: f(x) = -2 (x + 2)² - 4

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2 years ago

Which number is halfway between 1/2 and 2/3 ?

MariettaO [177]

For example, 3/5.

3/5 = 0.6.

1/2 = 0.5
2/3 = 0.6666

0.5 -- 0.6 -- 0.66666666

8 0

3 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

2 years ago

. The Empire State Building is a 102-story skyscraper. Its height is 1,250 ft. from the ground to the roof. The length and width

Aleks [24]

Answer: a) Dimensions of miniature is 0.17 × 0.08 × 0.5, b) 0.006 ft³.

Step-by-step explanation:

Since we have given that

Height of building = 1250 feet

Length of building = 424 ft

Width of building = 187 ft

Now, we know that The miniature version is just 1/ 2500 of the size of the original.

So, Height of miniature would be

$\dfrac{1250}{2500}=0.5\ ft$

Length of miniature would be

$\dfrac{424}{2500}=0.17\ ft$

Width of miniature would be

$\dfrac{187}{2500}=0.08\ ft$

a) What are the dimensions of the miniature Empire State Building?

Dimensions of miniature is 0.17 × 0.08 × 0.5

b. Determine the volume of the miniature building. Explain how you determined the volume.

$Volume=0.5\times 0.08\times 0.17=0.006\ ft^3$

Hence, a) Dimensions of miniature is 0.17 × 0.08 × 0.5, b) 0.006 ft³.

6 0

3 years ago