GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Answer:
11/15
Step-by-step explanation:
22/30 = 11/15 because they both have a common factor of 2 in the numerator and denominator.
"Increased" means to add.
"Quotient" is a total of a division problem.
"A number" means the unknown.
This is our problem: 3 + 6 / N
0.833333333% is the answer
Answer:
D
Step-by-step explanation:
So it'd be
28=3s+4
28-4=3s
24=3s
24/3=3s/3
8=2
