Answer:
C. (-1, 3)
Step-by-step explanation:
Label the 2 equations:
5y= 7x +22 -----(1)
x= -6y +17 -----(2)
Substitute (2) into (1):
5y= 7(-6y +17) +22
5y= -42y +119 +22 <em>(</em><em>Expand</em><em> </em><em>bracket</em><em>)</em>
5y= -42y +141 <em>(</em><em>Simplify</em><em>)</em>
42y +5y= 141 <em>(</em><em>+</em><em>42y</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
47y= 141
y= 141 ÷47 <em>(</em><em>÷</em><em>4</em><em>7</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
y= 3
Substitute y= 3 into (2):
x= -6(3) +17
x= -18 +17
x= -1
Thus, the solution is (-1, 3).
The answer is 56m^2.
The formula for finding area of a triangle is A=b•h/2.
So the base is 16m and the height is 7m. 16m•7m=112m^2
Now divide 112m^2 by 2.
112m^2/2=56m^2
42
(125/3 = 41.6..., 41.6... rounded is 42)
8/12 is left
3/4 is equivalent to 9/12 (multiply by 3)
9/12 minus 1/12 is 8/12
Answer 1.)is 196 simplify 7^2 to 49 6*(49-15)-2^3. Do 49-15=34 6*34-2^3. Do 2^3 to 8 6*34-8 =204-8 which is 196 hope this helps you
