Answer:10.8 units
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
First figure out the equation:
We know this is a linear equation because it appears to have a constant slope
Its y-intercept is where it passes in the y-axis, so it's -8
Furthermore, you should also figure out the slope. Notice that the y value increments by 3 every 1 x-value. Rise/Run is 3/1 = 3. Thus, the slope is 3
So your equation is g(x) = 3x - 8
Now we find our inverse function, which is just swapping the x-y values.
Thus, inverse of g(x) ==> y = 3x - 8 ==> x = 3y - 8 ==> x+8 = 3y ==> 
Plug in 7 for x and you get 5
<span>In this formula :
</span><span>y </span>tells us how far up the line goes
<span>x </span>tells us how far along
<span>m </span>is the Slope or Gradient i.e. how steep the line is
<span>b </span>is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the<span> line properties.</span><span> We shall now graph the line </span><span> 3x+2y-62 = 0</span><span> and calculate its properties
</span>
Notice that when x = 0 the value of y is 31/1 so this line "cuts" the y axis at y=31.00000
<span> y-intercept = 62/2 = 31
</span>
When y = 0 the value of x is 62/3 Our line therefore "cuts" the x axis at x=20.66667
<span> x-intercept = 62/3 = 20.66667
</span>
Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 31.000 and for x=2.000, the value of y is 28.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 28.000 - 31.000 = -3.000 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)
<span> Slope = -3.000/2.000 = -1.500
</span><span>
1.Slope = -3.000/2.000 = -1.500
2.x-intercept = 62/3 = 20.66667<span>
3.y-intercept = 62/2 = 31
I got sources from a few websites so excuse if something is weird/wrong.
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The answer is C Because 60x is implying 60 by a variable and the + 2000 Implies it’s already at 2000
Below is the solution, I hope it helps.
<span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10)
= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to:
= 8*tan(10)/{1 - 3*tan²(10)}
iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10)
= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)}
= 3*tan(30) = 3*(1/√3) = √3 [Proved]
[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)},
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
