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dmitriy555 [2]
3 years ago
8

Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams

can be formed from the 8 students?
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
6 0
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have

C(8,3) = 8!/(8-3)!3!
C(8,3) = 56

There are 56 3-person teams that can be formed from the 8 students. 
IrinaK [193]3 years ago
3 0

Answer:

it would be 56

Step-by-step explanation:

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Which of these ratios are equivalent? 4/6, 10/25 and 6/15
spayn [35]
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3 0
4 years ago
Read 2 more answers
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avanturin [10]

Answer:

  • c. 126.27 square feet

Step-by-step explanation:

<u>Area of rhombus is:</u>

  • A = pq/2, where p and q are diagonals

<u>We have:</u>

  • p = 18.3 ft
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4 0
2 years ago
Helpppppppppppppppppp
Brilliant_brown [7]

Answer:

<em>Option A; the tournament did begin with 128 teams</em>

Step-by-step explanation:

We can see that this equation is represented by compound interest, in other words an exponential function, either being exponential growth or exponential decay;

f ( x ) = a + ( b )^x, where a ⇒ start value, b ⇒ constant, x ⇒ ( almost always considered ) time, but in this case rounds

Option A; The equation is given to be t ( x ) = 128 * ( 1/2 )^x. Given by the above, 128 should represent the start value, hinting that the tournament <em>did indeed begin with 128 teams</em>

Option B; As the rounds increase the number of teams approach 128. Now mind you 128 is the start value, not the end value, which would mean that <em>this statement is false</em>

Option C; The tournament began with 1/2 teams. Theoretically that would not be possible, but besides that the tournament began with 128 teams, only differed by 1/2 times as much every round. <em>This statement is thus false</em>

Option D; This situation actually represents exponential decay. If each round the number of teams differed by 1/2 times as much, the number of teams remaining is less than before, and thus this models exponential decay, not growth<em> ( statement is false )</em>

<em>Answer : Option A; the tournament did begin with 128 teams</em>

4 0
3 years ago
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