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dmitriy555 [2]
3 years ago
8

Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams

can be formed from the 8 students?
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
6 0
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have

C(8,3) = 8!/(8-3)!3!
C(8,3) = 56

There are 56 3-person teams that can be formed from the 8 students. 
IrinaK [193]3 years ago
3 0

Answer:

it would be 56

Step-by-step explanation:

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