3 years ago

Given f(x)=x - 1/x and g(X)+ 1/x. what is f(g(1/2))?

Mathematics

1 answer:

Debora [2.8K]3 years ago

3 0

Assuming the plus sign is supposed to be an equal sign, the answer is 3/2. If not, the answer is 21/10.

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On the coordinate plane, point P is located at (3, y) and point Q is located at (1, -4). The distance between

Ivan

Answer:

y = 23, -31

Step-by-step explanation

ttyl

6 0

3 years ago

Trent's mom grave him $30. He earned another $12 completing chores. Trent spent $15 at the movie theater and $6 on lunch. How mu

cluponka [151]

30+12=42
15+6=21
42-21=21
Trent has $21 dollars left.

8 0

3 years ago

Read 2 more answers

Which number line shows the solution set to this inequality? -2x + 9 < x − 9

kotykmax [81]

Answer:

see below

Step-by-step explanation:

-2x + 9 < x − 9

Add 2x to each side

2x-2x + 9 < 2x+x − 9

9 < 3x-9

Add 9 to each side

9+9 < 3x

18 < 3x

Divide each side by 3

18/3 < 3x/3

6 < x

Open circle at 6 line going to the right

5 0

3 years ago

Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th

xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is $\bold{W=-3e^{7x}}$

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

$W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|$

Thus replacing the functions of the exercise we get:

$W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|$

Working with the determinant we get

$W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}$

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0

3 years ago

Write in numeral form 4*100+2*10+8(6*1/10) +(1*1/100)

Mice21 [21]

Answer:428 7/100

Step-by-step explanation:

5 0

3 years ago