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djverab [1.8K]
3 years ago
6

PLEASE HELP ME ASAP!!

Mathematics
1 answer:
solong [7]3 years ago
5 0
We have to find midpoint M of the diagonal AC (or BD, there is no difference) so:

M=\left(\dfrac{x_A+x_C}{2},\dfrac{y_A+y_C}{2}\right)=\left(\dfrac{-2+4}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{2}{2},\dfrac{2}{2}\right)=\\\\\\=\boxed{(1,1)}
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Given:

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