4 years ago

PLEASE HELP ME ASAP!!

1 answer:

5 0

We have to find midpoint M of the diagonal AC (or BD, there is no difference) so:

$M=\left(\dfrac{x_A+x_C}{2},\dfrac{y_A+y_C}{2}\right)=\left(\dfrac{-2+4}{2},\dfrac{4+(-2)}{2}\right)=\left(\dfrac{2}{2},\dfrac{2}{2}\right)=\\\\\\=\boxed{(1,1)}$

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