Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
F(-1) = 12 - 5(-1)
f(-1) = 12 + 5
Solution: f(-1) = 17
Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠LOM+m∠MON=m∠LON ----> by angle addition postulate
we have
m∠LOM=2x°
m∠MON=x°
m∠LON=90° ----> is a right angle
substitute the values

solve for x


X + 2x + 5 = 62 which can be turned into.
3x + 5 = 62
-5 -5 now we subtract 5 from each side
3x = 57
/3 /3 now we divide 3 from each side to get...
x = 19.
Now to check 19 + (2 x 19) + 5 does in fact equal 62. Jenny is 19 years old. Hope this helped.