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3 years ago

Evaluate the expression

Mathematics

1 answer:

Nana76 [90]3 years ago

5 0

Answer:

0+7i

Step-by-step explanation:

$\sqrt{-49}=\sqrt{49}\sqrt{-1}=7i=\boxed{0+7i}$

The real part of the expression ('a') is zero. We have shown that, so it will be in the required form. Ordinarily, 0 would not be shown when writing this number.

We have taken the question to mean the principal square root. -7i is also a root of -49.

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Which has a positive value in Quadrant III?

Tresset [83]

Tangent only has a positive valise in Quadrant III

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3 years ago

Read 2 more answers

Determine the missing value!

xz_007 [3.2K]

Hi there!

missing value: -9

1.Multiply the two negative:

$-2$ · $-4=-8$

2.Find the value of 72*-8:

$72*-8=-9$

Therefore, the missing value is -9.

4 0

3 years ago

Anybody knows how to do this ?????

Afina-wow [57]

Answer:

the quickest way would be to "complete the square"

on x^2 + 5x - 7

you will end up with (x+2.5)² = 13.25

y = (x+2.5)²-13.25

the vertex

VERTEX: (-2.5,-13.25)

Solution/X-Intercepts: -6.14 AND 1.14

Step-by-step explanation:

3 0

3 years ago

Karmen returned a bicycle to Earl's Bike Shop. The sales receipt showed a total paid price of $211.86, including the 7% sales ta

MakcuM [25]

Answer:

$198

Step-by-step explanation:

198x.07=13.86

198+13.86=211.86

7 0

4 years ago

CAN YOU HELP WITH THIS ONE QUESTION , JUST TRYING TO GET BACK ON HONOR ROLL !

Ivanshal [37]

Answer:

B. TRUE.

(3, 2) is the intersection point of the graphs of

x + y = 5 and x - y = 1.

Step-by-step explanation:

Option B is TRUE because intersection point should satisfy both the equation

and in option be it comes true.

i.e x = 3 and y = 2 we have

3 + 2 = 5 and 3 - 2 = 1

5 = 5 and 1 = 1

Hence TRUE

(3, 2) is the intersection point of the graphs of

3x + 2y = 5 and 3x - 2y = 1.

i.e x = 3 and y = 2 we have

3×3 + 2×2 = 5 and 3×3 - 2×2 = 1

13 ≠ 5 and 5 ≠ 1

Hence FALSE

(5, 1) is the intersection point of the graphs of

3x + 2y = 5 and 3x - 2y = 1.

i.e x = 5 and y = 1 we have

3×5 + 2×3 = 5 and 3×5 - 2×3 = 1

21 ≠ 5 and 9 ≠ 1

Hence FALSE

(5, 1) is the intersection point of the graphs of

x + y = 5 and x - y = 1.

i.e x = 5 and y = 1 we have

5 + 1 = 5 and 5 - 1 = 1

6 ≠ 5 and 4 ≠ 1

Hence FALSE

6 0

3 years ago