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2 years ago

Determine the line described by the given point and slope (0,0) and 2/3

Mathematics

1 answer:

AlekseyPX2 years ago

4 0

Answer:

The line is $y=\frac{2}{3} x$ .

Step-by-step explanation:

Given:

Point and slope (0,0) and 2/3.

Now, to determine the line.

Here the point is:

$(x_{1},y_{1}) =(0,0)$

And the slope is:

$m=\frac{2}{3}$

Now, putting the formula and substituting the value from above to determine the line:

$y-y_{1} = m(x-x_{1})$

$y-0=\frac{2}{3}(x-0)$

$y=\frac{2}{3} x$

Therefore, the line is $y=\frac{2}{3} x$ .

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Answer:

45 cm²

Step-by-step explanation:

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1 year ago

5x6-1+3=28 brackets or braces should be added

Artyom0805 [142]

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2 years ago

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Irina18 [472]

Answer:

Candidates are chosen without replacement, thus trials are dependent, meaning that Y has a hypergeometric distribution.

Step-by-step explanation:

Difference between hypergeometric and binomial distributions:

In the hypergeometric distribution, trials are dependent of other trials, while in the binomial distribution, they are independent. This can be examplified that in the hypergeometric distribution, the candidates are chosen from a set without replacement, while in the binomial distribution they are chosen with replacement.

In this question:

Candidates are chosen without replacement, thus trials are dependent, meaning that Y has a hypergeometric distribution.

6 0

2 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.