Answer:
The graph has a domain of all real numbers.
The graph has a y-intercept at 
.
The graph has an x-intercept at 
.
Step-by-step explanation:
Given: The graph is ![y=\sqrt[3]{x-1}+2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2)
The domain of a function is a set of input values for which the function is real and defined.
Thus, the graph has a domain of 
.
To find the y-intercept: To find the y-intercept, substitute 
in .
![\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dy%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C%26%3D%5Csqrt%5B3%5D%7B0-1%7D%2B2%20%5C%5C%26%3D-1%2B2%20%5C%5C%26%3D1%5Cend%7Baligned%7D)
Thus, the y-intercept is
To find the x-intercept: To find the x-intercept, substitute 
in .
![\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dy%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C0%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C-2%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%20%5C%5C%28-2%29%5E%7B3%7D%20%26%3D%28%5Csqrt%5B3%5D%7Bx-1%7D%29%5E%7B3%7D%20%5C%5C-8%20%26%3Dx-1%20%5C%5C-7%20%26%3Dx%5Cend%7Baligned%7D)
Thus, the x-intercept is
6x+9=3x+12
6x-3x=12-9
3x=3
X= 3
I hope this helps :)!
we have that
−4+8−16+32−.....
a1=-2*(-2)-----> -4
a2=-4*(-2)-----> +8
a3=+8*(-2)-----> -16
a4=-16*(-2)----> +32
a5=+32*(-2)----> -64
a6=-64*(-2)-----> +128
a7=+128*(-2)-----> -256
The sum of the first 7 terms of the series is
<span>[a1+a2+a3+a4+a5+a6+a7]-----> [-4+8-16+32-64+128-256]------->
-172</span>
<span>
the answer is -172</span>
I believe your answer is D if i am wrong i am deeply sorry.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Using PEMDAS rule
Parentheses, Exponents , Multiplication, Division, Addition, Subtraction
![\sf{4 [ 3 + 3(5 - 1) ]}](https://tex.z-dn.net/?f=%20%5Csf%7B4%20%5B%203%20%2B%203%285%20-%201%29%20%5D%7D)
Subtract 1 from 5
![\longrightarrow{ \sf{4 [3 + 3 \times 4 ]}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B4%20%5B3%20%2B%203%20%5Ctimes%204%20%20%5D%7D%7D)
Multiply the numbers : 3 and 4
![\longrightarrow{ \sf{4 [ 3 + 12 ]}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B4%20%5B%203%20%2B%2012%20%20%5D%7D%7D)
Add the numbers : 3 and 12
Multiply the numbers : 4 and 15
Hope I helped!
Best regards! :D
