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elena55 [62]
3 years ago
13

Oliver spot frustrated sometimes with his somewhat limited set of red We, and green building bricks. Part way through project, h

e often machines that transform brick of one colour into a combination of cut of bricks of one particular colour. So he invented some 3D printing bricks of one or more colours, Ench machine can also operate in re The red machine (R) converts I red brick (r) into I blue brick (b) 1 groet brick (g). This process and its reverse are represented by R-1 R bg and be Similarly, for the blue machine (B) we have B B- b Tg and Tg +b. And for the green machine (G) we have G-1 g rb and rb The machines can be used on collections of bricks, performing one con version at a time. For example, 3 blue bricks can be converted into 1 red and 3 green bricks in three steps, as follows: B B G- bbb rgbbrgrgb rggg Note that the order of the bricks in each collection is irrelevant. a Show how Oliver can convert 1 red brick into 3 red bricks. b Show how Oliver can convert 1 red brick into 5 red bricks in six steps. c Explain why Oliver cannot convert 1 red brick into 5 red bricks in less than six steps. d Oliver starts with a collection of bricks in which the combined number of blue and green bricks is odd. Explain why he cannot end up with a combined number of blue and green bricks that is even
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer: That is the answer for the first one and ill let you know if i work out more.

Step-by-step explanation:

Pavlova-9 [17]3 years ago
5 0

Answer:

that I have a panda but the black on it and I have a ok that you can come over for a few days to come back and I was in work today and it is a very long day at the end with the kids to school tomorrow right ha I have a panda but the black one of the day I can get some

over the place

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pickupchik [31]
Your correct answer is letter D
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2 years ago
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Plz help 14 points
ValentinkaMS [17]
 1)Rewrite the table:
70,  49,  34.3,  24.01,  11.807 {The original size of the wound =70}

2) write the quotient of each number by the number before & notice the value:

49/70= 0.7
34.3/49 = 0.7
24.01/34.3 =0.7
16.0807/24.01 = 0.67 ≈0.7
You notice this is a geometric progression with r 0.7
The last term in a GP =ar^⁽ⁿ⁻¹⁾


3) Domain and Range of this function:
Last term = a₁.rⁿ⁻¹. let last term be y==> f(n) = y =70(0.7)ⁿ⁻¹
or f(n) = y = 70(0.7)ⁿ / 0.7==> f(n) = [(0.7)ⁿ ]/ 100.
This is a decreasing exponential function where the coefficient
raised to n is < 1.
The domain is for all n>= 0.
When n→∞, f(n)→0; For n=0==>f(n) =70. So the range of f(n) is:<=70

7 0
3 years ago
A motorist traveled 250 miles on 11 gallons of gas. With the same vehicle, about how far could he go on 16 gallons of gas? A) 17
Andrei [34K]
ANSWER

363.6 \: miles
EXPLANATION

We were told that the motorist travelled 250 miles on 11 gallons of gas. This implies that,

250 \: miles \equiv11 \: gallons

Now we want to find how far he could go on 16 gallons.

x \: miles \equiv16 \: gallons


All other things being equal, the motorist should cover more than 250 miles with 16 gallons of gas.

Recall that: If more, less divides.

This implies that,

x =  \frac{250 \times 16}{11}




x =  \frac{4000}{11}   = 363.6 \: miles


Therefore the correct answer is C.

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I think, im not sure, it is skew left, median & 9

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Dividend

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9x+6

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