If (x - 2) is a factor of 2x³ + x² - 3 then for the value of x = 2 the polynominal is equal zero.
Substitute:
2 · 2³ + 2² - 3 = 2 · 8 + 4 - 3 = 16 + 4 - 3 = 17 ≠ 0
Answer: B) (x - 2) is not a factor.
Answer:
(6,8)
Step-by-step explanation:
midpoint=(x1+x2)÷2,(y1+y2)÷2
a(4,15) b(8,1)
x=4+8=12÷2=6
y=15+1=16÷2=8
Answer=(6,8)
Answer: P=47 inches
Step-by-step explanation:
First, you have to find the other side lengths. Two of the sides are equal to 20 because this is a rectangle. The first blank would be 20 because 20 times the other side length is equal to 70. Then you would divide 70 by 20 which would equal x. x would equal 3.5 in. Then the perimeter would be:
2(20)+2(3.5)=P
P=47 inches
Answer:
is the answer.
Step-by-step explanation:
Given:
<u>Step 1: Converting the mixed fraction into fraction:</u>
Multiply 4 by 2 add 1 to the result.
<u></u> =
=
=
<u>Step 2: Performing the multiplication using the fraction</u>
= >
=>
<u>Step 3: Converting the product back to mixed fraction </u>
divide 81 by 16 and find the remainder
=>
Dividing 81 by 16 we get 5 as quotient and 1 as remainder
Thus the result in mixed fraction will be
=>
Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
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Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width