This code attempts to fuse two strings together. So,
fuse("Apple", "Banana")
would return "ABpapnlaen a"
However, there are a couple of things wrong with this code:
- The for loop is incomplete (probably a copy paste error)
- It is unclear from the code if the array jawaban will overflow if kata1 and kata2 are large (it probably will)
- Biggest problem: the jawaban array is declared on the stack, which means it will be cleaned up when the function returns. So the caller of this function will reference unallocated memory! This is a huge bug!!
Answer:
The answer is "Option a"
Explanation:
Split-scope is also an easy and simple approach to deliver DHCP consistency and workload management into your system. Server 2008 R2 provides a convenient divide-scope guide which removes several operational efforts but can only be to use if all databases run on R2, and wrong choices can be described as follows:
- In option b, It uses the Ip address for multicast, that's why it is wrong.
- In option c, It is wrong because it uses a windows interface, that works on policies.
- In option d, It is wrong because it is an administrative feature.
"C" is the correct answer, if its correct please mark me brainliest.
2**(32 - netmask) - 2 = number of nodes available
The netmask is in CIDR (Common Internet Domain Routing) notation, without the slash.
One of the nodes would be needed for a router or else you can't communicate with other networks.
