Quadrilateral ABCD is inscribed in circle P as shown. Which statement is necessarily true?

Mathematics

1 answer:

DochEvi [55]3 years ago

8 0

Answer:

B. m∠A + m∠C = m∠B + m∠D

Step-by-step explanation:

To inscribe a quadrilateral in a circle, the sums of its opposite angles must be equal (each sum of its opposite angles equals 180 °)

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Please help, thanks.

Gnesinka [82]

4(c-d) is the answer bc the difference of (c-d) is done first, then multiplied by 4

4 0

3 years ago

Write in simplest form

Gnoma [55]

Find the commomon denominator of 6 and 5.

It's 6 · 5 = 30.

$\dfrac{5}{6}=\dfrac{5\cdot5}{6\cdot5}=\dfrac{25}{30}\\\\\dfrac{1}{5}=\dfrac{1\cdot6}{5\cdot6}=\dfrac{6}{30}$

$\left(\dfrac{5}{6}-\dfrac{1}{5}\right)\div\dfrac{4}{5}=\left(\dfrac{25}{30}-\dfrac{6}{30}\right)\div\dfrac{4}{5}=\dfrac{25-6}{30}\div\dfrac{4}{5}=\dfrac{19}{30}\div\dfrac{4}{5}$

Divide by fraction is the same like multiply by reciprocal of this fraction:

$=\dfrac{19}{30}\cdot\dfrac{5}{4}=\dfrac{19}{6}\cdot\dfrac{1}{4}=\dfrac{19}{24}$

4 0

3 years ago

Let f(x) = (x − 3)−2. find all values of c in (1, 4) such that f(4) − f(1) = f '(c)(4 − 1). (enter your answers as a comma-separ

Verizon [17]

If the function is $(x-3)^{-2}$ and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.

Given function is $(x-3)^{-2}$ and f(4) − f(1) = f '(c)(4 − 1).

In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.

We begin by calculating f(2) and f(5):

f(2)= $(2-3)^{-2}$