Quadrilateral ABCD is inscribed in circle P as shown. Which statement is necessarily true?

What is 10 + 10 help please make it for the dog

Nimfa-mama [501]

The answer to 10+10 is 20. I hope I made it for the dog.

4 0

3 years ago

Elizabeth has 1 7/10 as many plants as Rosalie has in her arden. If Elizabeth has 51 plants, how many plants does Rosalie have i

dexar [7]

Question: Elizabeth has 1 7/10 as many plants as Rosalie has in her garden. If Elizabeth has 51 plants, how many plants does Rosalie have in her garden?

Answer: X=30

explanation:

1 7/10 can be rewritten as 1.7

x=amount of plants that Rosalie has

x=1.7/51

x=30

question answered by

(jacemorris04)

4 0

3 years ago

Alligator 1 initial weight is 4 lbs. the rate of growth is 2 lbs. per month. Alligator 2 initial weight is 8 lbs. the rate of gr

LekaFEV [45]

Answer:

4 months

Step-by-step explanation:

Let the number of months be x

Alligator 1 weight = 4 + 2x

Alligator 2 weight = 8 + x

4 + 2x = 8 + x
2x - x = 8 - 4
x = 4

The answer is 4 months

7 0

3 years ago

An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t

erastova [34]

Answer:

$z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23$

The p value would be given by:

$p_v =2*P(z$

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

$\bar X=46.5$ represent the mean

$\sigma=1.1$ represent the population standard deviation

$n=150$ sample size

$\mu_o =46.7$ represent the value to verify

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:

Null hypothesis: $\mu = 46.7$

Alternative hypothesis: $\mu \neq 46.7$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23$

The p value would be given by:

$p_v =2*P(z$

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0

3 years ago

Assume that f(1000)=50 , and it's also true that the cost to the consumer of each item is $5, did the retailer make wise use of

andriy [413]

I would say that they didnt because if you plug anythin in that equation it wont be a solution......i think thats what it meant

4 0

3 years ago