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Alenkasestr [34]
3 years ago
8

2.) Solve 2.3 (Simplify your answer)please and thank you!!!​

Mathematics
1 answer:
kumpel [21]3 years ago
6 0

2.3 as a simplified fraction is 23/10, 2 and 3/10, or even as a percentage, 230%.

Hope this helps, if not, comment below please!!!

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6 0
2 years ago
For questions 1 and 2, use factoring to find the x-intercepts of these quadratic equations.
Marysya12 [62]
1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2

(X+2)=0 therefore x= -2

2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
6 0
2 years ago
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
2x+2y=8 in function form step by step please?
nasty-shy [4]
You could get two different functions out of this:

<u>2x + 2y = 8</u>

1). <u> 'y' as a function of 'x'</u>

Subtract  2x  from each side:  2y  = -2x + 8

Divide each side by  2 :         <em> y  =  -x + 4</em>


2). <u> 'x' as a function of 'y' :</u>

Subtract  2y  from each side:    2x  =  -2y + 8

Divide each side by  2 :        <em>  x  =  -y + 4</em>

Those two functions look the same, but that's just because the original
equation given in the problem was so symmetrical.  In general, they're
not the same function.


7 0
3 years ago
Read 2 more answers
3. Label the matrix according to the dimensions. *
Lelechka [254]
Add a picture please
8 0
3 years ago
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