Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
Answer:
y = -2 ( (x^2) + (2*x*5) + (5^2)) - 30
y = -2 ( x^2 + 10x + 25) - 30
y = -2x^2 - 20x - (2*25) - 30
y = -2x^2 - 20x - 50 - 30
y = -2x^2 - 20x - 80
Answer:
5 units
Step-by-step explanation:
If point T is on the line segment SU, then ST + TU = SU.
Given
TU = 4x + 1
SU = 8
ST = 3x
To get TU, we need to get the value of x first. To get x, we will substitute the given parameters into the formula;
3x+4x+1 = 8
7x+1 = 8
subtract 1 from both sides
7x+1-1 = 8-1
7x = 7
divide both sides by 7
7x/7 = 7/7
x = 1
Substitute x = 1 into the length TU
Since TU = 4x+1
TU = 4(1)+1
TU = 5
Hence the numerical length of TU is 5 units
Answer:
C. 3 3/4
Step-by-step explanation:
