What is 11/12 x 4/5

Cat behavior: A report stated that the average number of times a cat returns to it's good bowl during the day is 37. Assuming th

Virty [35]

Answer:

P (34<X<39) = 0.5899

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 37, \sigma = 3$

What is the probability that a cat would return to it's dish between 34 and 39 times a day.

This is the pvalue of Z when X = 39 subtracted by the pvalue of Z when X = 34. So

X = 39

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39 - 37}{3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486

X = 34

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{34 - 37}{3}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.7486 - 0.1587 = 0.5899

So

P (34<X<39) = 0.5899

6 0

3 years ago

How to solve and answer for 4 1/3 - 2 1/5 ?

gregori [183]

Answer : 2 2/15

To begin you need to convert the fractions into something they both can go into. Sometimes it is easier to multiple the two denominator of the fractions, which in this case it is.
So, 3 times 5 is 15
This means your going to convert your fraction into 15th

1/3 is 5/15
This is because you need to times the bottom by 5 in order to get 15, so you need to do the same with the top.

1/5 is 3/15
This is because you need to times the bottom by 3 to get 15 so you do the same with the top

Next you just subtract the amounts separately
4-2 = 2
5/15 - 3/15 = 2/15

This means your answer is 2 2/15

6 0

2 years ago

Read 2 more answers

Write down a fraction that lies halfway between 1/3 and 1/2

lorasvet [3.4K]

You need to find a common denominator. I would use 6 first.

1/3 is equivalent to 2/6. 1/2 is equivalent to 3/6. It is still difficult to find the median between the two so I would try 12 as a common denominator.

1/3 is equivalent to 4/12, and 1/2 is equivalent to 6/12. Therefore, the halfway point would be:

5/12

5 0

4 years ago

A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked

kogti [31]

A) The probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) The probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) The probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E ) the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

Step-by-step explanation:

Here, the total number of black neckties = 6

The total number of white neckties = 2

The total number of red neckties = 4

The total number of maroon neckties = 2

The total number of blue neckties = 2

The number of times the experiment is repeated = 300

A ) P(Picking a white tie) = $\frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}$

= $\frac{2}{16} = \frac{1}{8}$

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) P(Picking a BLUE tie) = $\frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) P(Picking a Red tie) = $\frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16} = \frac{1}{4}$

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) P(Picking a Black tie) = $\frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16} = \frac{3}{8}$

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E) P(Picking a maroon tie) = $\frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) P(Picking a NOT whiten tie) = 1 - P( picking a white tie)

$= 1-(\frac{1}{8} ) = \frac{8-1}{8} = (\frac{7}{8} )$

So, the probability of NOT picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

4 0

3 years ago

A vendor sells pizza and soft drinks.A customer buys 8 slices of pizza and 6 drinks for$ 39.50.Another customer buys 5 slices of

otez555 [7]

Answer:

$3.61

Step-by-step explanation:

let p represent pizza and d represent drink, then

8p + 6d = 39.5 → (1)

5p + 7d = 30.44 → (2)

Multiplying (1) by 7 and (2) by - 6 and adding will eliminate d

56p + 42d = 276.5 → (3)

- 30p - 42d = - 182.64 → (4)

Add (3) and (4) term by term

(56p - 30p) + (42d- 42d) = (276.5 - 182.64), that is

26p = 93.86 ( divide both sides by 26 )

p = 3.61

That is a slice of pizza costs $3.61

7 0

4 years ago