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snow_lady [41]
3 years ago
13

Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% chance that the land has oil.

Jason decides to test the land for oil. He buys a kit that claims to have an 80% accuracy rate of indicating oil in the soil. What is the probability that the land has no oil and the test predicts it has oil?
Mathematics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

Don't take my word for it but I think it would be 55% chance. I'm Probably wrong.

Step-by-step explanation:

Jet001 [13]3 years ago
5 0

Answer:

9% or 0.09

Step-by-step explanation:

Given, chance of land having oil is 45%. Which is 0.45

So, chance of land NOT having oil is  percent. Which is 0.55

Given, kit's accuracy rate of finding oil as 80%. Which is 0.80

So, kit's accuracy rate of NOT finding oil is   percent. Which is 0.20

These 2 events are INDEPENDENT, which means that the probability of one event occurring does not affect the probability of another event occuring.

The formula, if we let the two evens be A and B, is:

P(A and B)=P(A) * P(B)

Now, "the probability that the land has oil (event A)AND the test predicts that there is no oil (event B)" will be:

P(A and B) = P(A) * P(B)

Hence, the probability is 0.09 or 9%

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2 years ago
For what value(s) of k will the relation not be a function
skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

k-8.3+2.4k=-\frac{3}{4} k

3.4k-8.3=-\frac{3}{4}k

3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10

4k-83=-\frac{15}{2}k

34k=-\frac{15}{2}k+83

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(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

2-|k+1|=-6

2-\left|k+1\right|-2=-6-2

-\left|k+1\right|=-8

\left|k+1\right|=8

Since, this is absolute function

so, we can break it into two parts

|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a

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k=-9\quad \mathrm{or}\quad \:k=7...............Answer

5 0
3 years ago
An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0
zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 0.9

So

\mu = E(X) = np = 105*0.9 = 94.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07

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100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 94.5}{3.07}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

96.33% probability that everyone who appears for the flight will get a seat

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