Answer:
Every organism possesses in its ribosome a protein that is similar to rpl4. This protein has an amino acid sequence that is similar to the sequence of E. coli’s rpl4.
Explanation:
Phylogenetic tree is a diagram which represents the similarities between different organisms and shows their evolutionary histories.
The presence of a similar genetic sequence or amino acid sequence shows that the gene is common in all those organisms. This means that all organisms had a common ancestor through which the gene or amino acid was transferred. The genetic r amino acid sequence remained common in all the different organisms.
Answer:
1 . The stage on the first meiotic division when the homologous chromosomes move to opposite poles but the sister chromatids remain together
: b. Anaphase I
2 . The stage in the second meiotic division where sister chromatids migrate to opposite poles
: c. Anaphase II
3 . A structure on the chromosome that holds a pair of chromatids together during replication
: f. centromere
4 . A double-stranded chromosome following replication attached by a centromere
: d. chromatid
5 . A condition where non-sister chromatid of homologous chromosomes exchange genes
: e. crossing over
6 . The stage in the first meiotic division where the homologous chromosomes line up as a pair
: a. Metaphase I
7 . The stage in the second meiotic division where the chromatid pair lines up at the equator of the cell: g. Metaphase II
Explanation:
DNA replication occurs during the S phase of the interphase of the cell cycle. The replicated DNA molecules are accommodated in two sister chromatids of a chromosome that are held together by a centromere.
During prophase I, the chromatids of a homologous chromosome pair exchange a genetic segment. This process is called crossing over. It generates recombinant chromatids with new combinations of genes.
Metaphase I of meiosis I includes the alignment of homologous pairs of chromosomes at the cell's equator. This is followed by separation and movement of homologous chromosomes to the opposite poles of the cell during anaphase I.
Metaphase II of meiosis II includes the alignment of individual chromosomes, each with two sister chromatids, on the cell's equator. During anaphase II, splitting centromere separates the sister chromatids which then move to the opposite poles of the cell.
Hmm i think it might be a <span>covalent </span>bond
I hope you have a wonderful day! And hope this helps! :D
Answer:
1. How did the tidal wave affect the predicted frequencies of the alleles in the population?
No changes
2. What is the frequency of the recessive allele?
q= 0.6
Explanation:
If we assume that all individuals were equally likely to be wiped out, that means the frequency/ratio of the gene and genotype of the population will not change. The tidal wave killing 100 out of 200, so it simply makes the population become half of it used to be.
If the population at equilibrium, we can use the Hardy-Weinberg formula to find out the expected frequency of the dominant and recessive alleles. There are 36 homozygous recessives out of 100, so the frequency of the recessive allele will be:
q^2 = 36/100
q= √36/100= 6/10= 0.6