The value of theta where we do not have a vertical asymptote is θ = 0.
<h3>
Where we do not have a vertical asymptote?</h3>
The vertical asymptotes happen when the denominator becomes equal to zero.
For our case, we have:
tan(θ) = sin(θ)/cos(θ).
So the vertical asymptotes are for the values of θ where the cosine is equal to zero. Particularly, cos(0) = 1, then in θ = 0 the denominator is not equal to zero, which means that at that value we do not have an asymptote.
Then the correct option is B.
If you want to learn more about asymptotes.
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Answer:
12
Step-by-step explanation:
Use the Pythagorean theorem which is a^2 + b^2 = c^2
c is hypotenuse and a and b are the legs
we need to find a^2 so
a^2 + 16^2 = 20^2
a^22 + 256 = 400
then subtract 256 from 400
a^2 = 144
square root 144
= 12
Answer:
-8
Step-by-step explanation:
7x+6x+4+9=9x+5+3x
13x+13=12x+5
-12x -12x
x+13=5
-13 -13
x=-8
Answer:
y = -2x - 1 ; slope = -2, y-intercept = (0, -1)
Step-by-step explanation:
to get the slope and y intercept, you need to put the equation into slope-intercept form: y = mx + b
the term mx is the slope of the line, and b is the y-intercept
to do this, you need to solve for y, so get y by itself by subtracting 8x from the left side
8x + 4y = -4
-8x. -8x
4y = -8x - 4
divide both sides by 4 to get y alone
4y/4 = y
-8x/4 = -2x
-4/4 = -1
y = -2x - 1 is the final equation
the slope of the line is -2 (also can be said as -2/1), and the line intercepts the y-axis at (0,-1)
