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laila [671]
3 years ago
6

All rectangles are quadrilaterals. TrueFalse

Mathematics
2 answers:
mariarad [96]3 years ago
5 0

Answer:

yep

Step-by-step explanation:

yes always

weqwewe [10]3 years ago
4 0

Answer:

True

Step-by-step explanation:

A quadrilateral is a shape with 4 sides and 4 corners. A rectangle by definition is a plane figure with four straight sides and four right angles, especially one with unequal adjacent sides, in contrast to a square. Therefore, a rectangle is always a quadrilateral.

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PLS HELP I WILL GIVE BRAINLIEST
mr_godi [17]

Answer:

21 square feet

Step-by-step explanation:

To find out the area of this irregular figure, divide it into two rectangles and add their areas.. This can be done in two ways.

Version 1: 6 * 2 rectangle and 3 * 3 square

(6 * 2) + (3 * 3)

12 + 9

21 sq. ft.

Version 2: 5 * 3 rectangle + 2 * 3 rectangle

(5 * 3) + (2 * 3)

<em>You could really just do 7 * 3 here.</em>

7 * 3

21 sq. ft.

Either way, you still get 21 square feet as your answer.

5 0
3 years ago
True or false<br> To find the complement of an event (P(not A)), you solve 1-P(A).
PilotLPTM [1.2K]

Answer:

true

Step-by-step explanation:

7 0
2 years ago
Solve each of the following quadratic equations<br><br> 3x=0.5x^2<br><br><br> 0=5x^2-2x+6
UNO [17]

<u>Question 1</u>

<u />3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}

<u>Question 2</u>

<u />0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}

6 0
2 years ago
The height of a parallelogram is three times its base. If the area is 972 square inches, what is the base and height?
Fed [463]
So h is 3x 
b is x
3x plus x equal 972 
4x = 972 
243 is base 
243 times 3 is 729
8 0
3 years ago
Please help me fast I still nee to finish 2 more ixl's by monday!!!!
sleet_krkn [62]

Answer:No

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

3 0
2 years ago
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