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gogolik [260]
2 years ago
5

If i have 2 1/2 pans of brownie left, and my sister eats 1/3 of the brownies, how much of a pan has she eaten

Mathematics
2 answers:
Tomtit [17]2 years ago
3 0

Answer:

5/6 a pan of brownies.

Step-by-step explanation:

2 1/2=5/2, So you have 5/2 pans of brownies. If your sister eats 1/3 of these brownies we can write the equation 5/2*1/3=b=5/6, with variable b being how much of a pan of brownies your sister has eaten. Your sister has eaten 5/6 a pan of brownies.

PSYCHO15rus [73]2 years ago
3 0
5/6 is the answer because i just did it about three times and checked it
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Andrej [43]

Answer:

2k + 4 > k + 11

Step-by-step explanation:

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6 0
3 years ago
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6 0
3 years ago
B increased by 16 is at most 20 in equation form
Umnica [9.8K]

Answer:

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7 0
3 years ago
The rate at which the temperature is dropping is 6t 5t2 degrees Celsius per hour t hours after sundown. How much had the tempera
Whitepunk [10]

Using a differential equation, it is found that the temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

<h3>What is the differential equation that describes the temperature in t hours after sundown?</h3>

The rate at which the temperature is dropping is 6t + 5t^2 degrees Celsius per hour t hours after sundown, hence the <em>differential equation</em> is:

\frac{dT}{dt} = 6t + 5t^2

Applying <em>separation of variables</em>, we find the solution as follows:

\frac{dT}{dt} = 6t + 5t^2

dT = (6t + 5t^2) dt

\int dT = \int (6t + 5t^2) dt

T(t) = \frac{5t^3}{3} + 3t^2 + T(0)

In which T(0) is the temperature at sundown.

In 3 hours, the change will be of:

C = T(3) - T(0) = \frac{5t^3}{3} + 3t^2|_{t = 3}

Hence:

\frac{5(3)^3}{3} + 3(3)^2 = 45 + 27 = 72

The temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

You can learn more about differential equations at brainly.com/question/24348029

5 0
2 years ago
28 divided by 3/4<br><br><br><br><br><br> Please help!!!
Amanda [17]
For 28(3/4), the answer is 21
6 0
3 years ago
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