one angle is 3x-3
another angle is 6(x-10)
Both angles are vertically opposite angles
Vertically opposite angles are always equal
So we equation both the angles and solve for x
3x - 3= 6(x-10)
3x - 3 = 6x - 60
Subtract 6x from both sides
-3x - 3 = -60
Add 3 on both sides
-3x = -57
Divide by 3
x = 19
The value of x= 19
The other number is -3.
Step-by-step explanation:
Step 1; First we develop formulae for the given information. A number is added with 3 and the resulting sum is multiplied by 4. This number is then divided by 2 and the quotient is 0. Assume the unknown number is x, then the given information is as follows
The quotient of 
is 0. So = 0.
Step 2; Now we solve the above equation. The denominator is taken to the RHS and the RHS remains zero.
= 0, 4(x+3)= 0, 4x+ 12 = 0, 4x = -12, x = 
= -3.
So the other number is -3.
Answer:
About 40 students are left handed
Step-by-step explanation:
Its a distributive propertyyyyyyy.
Step-by-step explanation:
a). A = {x ∈ R I 5x-8 < 7}
5x - 8 < 7 <=> 5x < 8+7 <=> 5x < 15 =>
x < 3 => A = (-∞ ; 3)
A ∩ N = {0 ; 1 ; 2}
A - N* = (-∞ ; 3) - {1 ; 2}
b). A = { x ∈ R I 7x+2 ≤ 9}
7x+2 ≤ 9 <=> 7x ≤ 7 => x ≤ 1 => x ∈ (-∞ ; 1]
A ∩ N = {0 ; 1}
A-N* = (-∞ ; 1)
c). A = { x ∈ R I I 2x-1 I < 5}
I 2x-1 I < 5 <=> -5 ≤ 2x-1 ≤ 5 <=>
-4 ≤ 2x ≤ 6 <=> -2 ≤ x ≤ 3 => x ∈ [-2 ; 3]
A ∩ N = {0 ; 1 ; 2 ; 3}
A - N* = [-2 ; 3) - {1 ; 2}
d). A = {x ∈ R I I 6-3x I ≤ 9}
I 6-3x I ≤ 9 <=> -9 ≤ 6-3x ≤ 9 <=>
-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3 =>
-3 ≤ x ≤ 5 => x ∈ [-3 ; 5]
A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}
A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}
