Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
<h3>f(x) = -3·2^(x-1) -1</h3>
- reflection across the x-axis (multiplication by -1)
- vertical expansion by a factor of 3 (multiplication by 3)
- shift to the right 1 unit (replace x with x-1)
- shift down 1 unit (add -1 to the function value)
_____
<h3>f(x) = -1/4·2^(x+1) -1</h3>
You may notice this is the same as the previous question, but with the vertical expansion factor 1/4 instead of 3, and the horizontal shift left instead of right.
- reflection across the x-axis (multiplication by -1)
- vertical compression by a factor of 4 (multiplication by 1/4)
- shift to the left 1 unit (replace x with x+1)
- shift down 1 unit (add -1 to the function value)
Answer:
Step-by-step explanation:
Solving
5x + -2y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '2y' to each side of the equation.
5x + -2y + 2y = 12 + 2y
Combine like terms: -2y + 2y = 0
5x + 0 = 12 + 2y
5x = 12 + 2y
Divide each side by '5'.
x = 2.4 + 0.4y
Simplifying
x = 2.4 + 0.4y
Answer:
I would go with C.Line 4
Please mark brainliest!
Step-by-step explanation:
