Answer:
Total tickets = 70
Total cost = $550
Adult's ticket = $9
Child's ticket = $5
Difference = 9 - 5 = $4
Assume all 70 are child's tickets
5 x 70 = 350
But the total cost was 550
550 - 350 = $200
The $200 must have come from Adult's tickets, which has a difference of $4.
200 ÷ 4 = 50
So there are 50 adult's tickets.
70 - 50 = 20
And there are 20 child's tickets.
Hope this helps - Itz.Jordan
Answer:
B. The original purchase total must be at most to $44 before the discounts are applied.
Step-by-step explanation:
Solve the inequality by adding $10, then dividing by 0.8.
0.8x -$10 ≤ $25.20
0.8x ≤ $35.20 . . . . . . . . add $10
x ≤ $35.20/0.8 . . . . . . . divide by 0.8
x ≤ $44 . . . . . . . . . the before-discount purchase must be at most $44
I believe the answer is either C or D... I am not sure though..
Answer:
the y intercept
Step-by-step explanation:
the k in algebra is the y intercept :))
