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Alinara [238K]
3 years ago
12

24 times 31 equals show your work

Mathematics
2 answers:
aksik [14]3 years ago
8 0
   1   
   24  
<span>× 31
</span>----------
   24
 720
--------
 744

you line them up like above. you multiply the bottom number by the top. for example, the bottom place in the ones place is 1 and u multiply it by the ones place on the top number. you continue doing that to each number. but when you move on to the bottom number's tens place, u start below what u got for the ones place. u add a zero where the ones place is. but if u multiply for example 4 and 3 and get 12 which is greater than 10, u move ten to the next place so there should be a one on the next place. then u add the 2 numbers u get.
Anvisha [2.4K]3 years ago
7 0
 24
x31
-----------------
744
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A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

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