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3 years ago

How to write ten and twenty-four hundredths

Mathematics

1 answer:

DENIUS [597]3 years ago

8 0

The answer to this is 10.24

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Solve for Z. <br><br> 3z - 5 = 2z + 2

inna [77]

The answer to your equation is z = 7

7 0

2 years ago

If employment is expected to increase by 14.8% between 01/2009 and 01/2016 and the employees number 19, 100 in 01/2009, how many

AlexFokin [52]

Based on the rate of increase, the number of employees that will be there in 2016 is<u> 21,927 people.</u>

<h3>Number of employees in 2016</h3>

This can be calculated by the formula:

= Employees in 2009 x ( 1 + rate of increase)

Solving gives

= 19,100 x (1 + 14.8%)

= 21,926.8

= 21,927 people

In conclusion, there will be 21,927 people in 2016.

Find out more on rates of increase at brainly.com/question/3040628.

3 0

2 years ago

How many pounds does 64 ounces weigh?

wel

Answer:

4 lbs

Step-by-step explanation:

There are 16 ounces in a pound, so divide 64 by 16 to get the number of pounds. 64 ÷ 16 = 4 lbs

8 0

2 years ago

When solving for y in a equation what is the answer to 5x-3y=21

masha68 [24]

Answer:

y=53x-7

Step-by-step explanation:

5x-3y=21

-3y=-5x+21

divide by 3

y=5/3x-7

4 0

2 years ago

Read 2 more answers

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

2 years ago