By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Jim's time is 5:50 and John's time is 6:40.
Answer:
I=prt,,60=400*0.05t,,t=3 ..................
this is what i got i hope it is use full to you <3
Step-by-step explanation:
Ironically, buying a lot at a time is cheaper than buying bit by bit. Places like Sam's Club specialise in having bulk supplies. People might not be planning to buy bulk, but after seeing how cheap it is, they'll decide to buy more than they planned. It creates the illusion of saving money to the consumer, but in reality, they spent more just because they liked the idea of getting more product. Hope that made since! :D
