Answer:
shhheeeeeeesh that's is hard good luck

is conservative if there is a scalar function
such that
. This would require



(or perhaps the last partial derivative should be 4 to match up with the integral?)
From these equations we find





so
is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:


Answer:
<u>Part 1:</u>
For Platinum Gym:
90 + 30x
For Super Fit Gym:
200 + 20x
<u>Part 2:</u> $270
<u>Part 3:</u> $320
<u>Part 4:</u> 11 months
<u>Part 5:</u> See explanation below
Step-by-step explanation:
<u>Part 1:</u>
Let "x" be the number of months:
For Platinum Gym:
90 + 30x
For Super Fit Gym:
200 + 20x
<u>Part 2:</u>
We put x = 6 in platinum gym's equation and get our answer.
90 + 30x
90 + 30(6)
90 + 180
=$270
<u>Part 3:</u>
We put x = 6 into super fit's equation and get our answer.
200 + 20x
200 + 20(6)
200 + 120
=$320
<u>Part 4:</u>
To find the number of months for both gyms to cost same, we need to equate both equations and solve for x:
90 + 30x = 200 + 20x
10x = 110
x = 11
So 11 months
<u>Part 5:</u>
We know for 11 months, they will cost same. Let's check for 10 months and 12 months.
In 10 months:
Platinum = 90 + 30(10) = 390
Super Fit = 200 + 20(10) = 400
In 12 months:
Platinum = 90 + 30(12) = 450
Super Fit = 200 + 20(12) = 440
Thus, we can see that Platinum Gym is a better deal if you want to get membership for months less than 11 and Super Fit is a better deal if you want to get membership for months greater than 11.
Answer:
I believe it's the last one.