3 years ago

Please help me fast i need help please

1 answer:

8 0

The distribution is symmetric, I had the same exercise!!

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Savatey [412]

Answer:

patunayan Ang dakilang pag-ibig ni florante at laura

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3 years ago

Mama L [17]

Answer:C.It can be concluded, with 95% confidence, that between 81% and 85% of all employees will rate the vacation policy as "delightful."

Step-by-step explanation:

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3 years ago

Daniel [21]

1. -6.2f + 2.9f = -3.3f
2. -22-4 = -26
= -3.3f - 26

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2 years ago

Dominik [7]

Answer: B

Step-by-step explanation: I know

8 0

2 years ago

aev [14]

Answer: 0.9834

Step-by-step explanation:

Given : The test scores are normally distributed with

Mean : $\mu=\ 0$

Standard deviation : $\sigma= 1$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x = -2.13

$z=\dfrac{-2.13-0}{1}=-2.13$

For x = 3.88

$z=\dfrac{3.88-0}{1}=3.88$

The p-value = $P(-2.13$

$0.9999477-0.0165858=0.9833619\approx0.9834$

Hence, the probability that a given score is between negative 2.13 and 3.88 = 0.9834

3 0

4 years ago