Hello!
The equation can be written as seen below. You only need a y-intercept and slope to write the equation.
y=-2x+3 (it intercepts at a y-value of 3).
I hope this helps!
Writing and solving an equation of ratios is the way to go here. See if you can figure out why the following is correct:
x+3 x
----- = -------
12 x+3
Then (x+3)^2 = 12x, and x^2 + 6x + 9 = 12x, so that x^2 - 6x + 9 = 0
This is the square of (x - 3). Thus, x-3 = 0, and x = 3.
The value of x is 3.
Part A: Factor 3x2y2 − xy2 − 2y2. Show your work. (4 points)
3x^2y^2 − xy^2 − 2y^2
y^2 ( 3x^2 - x -2 )
y^2 (3x+2)( x - 1)
Part B: Factor x^2 + 6x + 9. Show your work. (3 points)
x^2 + 6x + 9
= x^2 + 2*3x + 3^2
= (x+3)(x+3)
= (x+3)^2
Part C: Factor x2 − 25. Show your work. (3 points)
x^2 - 5^2
<span>(x-5)(x+5)</span>
Answer:
y =
Step-by-step explanation:
From the given table,
Two points are (1, 15) and (7, 47)
If the two points and are lying on a line then slope 'm' of the line will be,
m =
=
=
=
Let the equation of a line passing through (h, k) is,
y - h = m(x - k)
If the line passes through (1, 15)
y - 1 =
y =
y =
y =
Answer:
x=-2+3t , y=-9-10t
Step-by-step explanation:
I'm going to start by solving the first equation for t....which will give (x-x1)/(x2-x1) =t.
You can now substitute this in the second equation to get....y=y1 + (y2-y1)(x-x1)/(x2-x1)
Rearranging, you get y-y1 = (y2-y1) / (x2-x1) * (x-x1) which is equivalent to y-y1= m(x-x1) which is the point-slope formula for a line.
So since t was varying between 0 and 1,
plugging in t=0 you get x=x1 and y = y1 givin you the coordinate (x1,y1)
similarly, plugging in t=1 leads to (x2,y2)
So this is a representation of a segment connecting these 2 points.
B) just plug in the points into your given formula from part a to get...
x=-2 +(1--2)t and y = 9 +(-1-9)t
or x=-2+3t , y=-9-10t