Answer:
x=-2+3t , y=-9-10t
Step-by-step explanation:
I'm going to start by solving the first equation for t....which will give (x-x1)/(x2-x1) =t.
You can now substitute this in the second equation to get....y=y1 + (y2-y1)(x-x1)/(x2-x1)
Rearranging, you get y-y1 = (y2-y1) / (x2-x1) * (x-x1) which is equivalent to y-y1= m(x-x1) which is the point-slope formula for a line.
So since t was varying between 0 and 1,
plugging in t=0 you get x=x1 and y = y1 givin you the coordinate (x1,y1)
similarly, plugging in t=1 leads to (x2,y2)
So this is a representation of a segment connecting these 2 points.
B) just plug in the points into your given formula from part a to get...
x=-2 +(1--2)t and y = 9 +(-1-9)t
or x=-2+3t , y=-9-10t
