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aleksley [76]
2 years ago
11

Regular hexagon ABCDEF is inscribed in a circle with center H. What is the image of segment BC after a reflection over line FC?

Mathematics
1 answer:
AlladinOne [14]2 years ago
5 0
Regular hexagon ABCDEF is inscribed in a circle with center H. What is the image of segment BC after a reflection over line FC?
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Vector V is in standard position and makes an angle of 50° with the positive x-axis. Its magnitude is 15. Write V in component f
Scilla [17]

Answer:

a=9.641, b=11.49

Vector will be 9.641 i + 11.49 j

Step-by-step explanation:

We have given that vector V has the magnitude of 15

And it makes an angle of 50^{\circ} with positive x axis

Now let the x component of vector V is a and y component of vector V is b

So a=Vcos\Theta =15\times cos50^{\circ}=9.641

b=Vsin\Theta =15\times sin50^{\circ}=11.49

In vector form 9.641 i+11.49 j

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3 years ago
Brian multiplied his average speed of 14.73 miles per hour by the amount of time he spent cross-country skiing. His product was
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Answer:

12.2*1=12.2

12.2*0.45=5.49

5.49+12.2=17.69

Step-by-step explanation:

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3 years ago
Please answer as soon as possible
alekssr [168]

Answer:8^1/6*2^x=32^1/2

We move all terms to the left:

8^1/6*2^x-(32^1/2)=0

Domain of the equation: 6*2^x!=0

x!=0/1

x!=0

x∈R

We get rid of parentheses

8^1/6*2^x-32^1/2=0

We calculate fractions

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The correct is a characteristic are idealized
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PLEASE HELP!! NO LINKS!! GIVING 12 POINTS AWAY!!
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