Point 
is a solution of the equation 
and point is not a solution of equation 
Why point <em> </em>is solution of the equation<em> </em> ?
If point is solution of the equation then they must satisfy the equation.
So we need to check one by one
equation
We can write as
So point is solution of this equation.
Equation
We can write as
So point is not solution of equation
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In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.
In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.
What would the graphs look like?
In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.
In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.
You move 9 units to the right duh
The percent of the mark down would be 10%. If you subtract 81 from 90, you get 9. Then divide 90 by 9 and you get 10. Hope this helps!
Answer: b and d
Step-by-step explanation:
Since the roots are x=2 and x=6, we can write the equation as
Substituting in the coordinates of the vertex,
So, the equation is 
.
On expanding, we get 
