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grigory [225]
3 years ago
15

What is the slope of a line that passes through (-4,-13) and (19,11)?

Mathematics
1 answer:
raketka [301]3 years ago
7 0
We can find the slope from the two given points using the standard formula:
m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}
m=\frac{11-(-13)}{19-(-4)}
m=\frac{24}{23}
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Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.
zheka24 [161]
The first thing I'd do is put this equation into standard slope - intercept form. 

12x - 5y = 2               Subtract 12x from each side
-5y = -12x + 2            Divide each side by -5 to isolate the <em>y 
</em><em />y = 12/5(x) - 2/5    
     
 The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)

y = mx + b                    Fill in the variables
3 = 12/5(2) + b             Simplify
3 = 24/5 + b                 Subtract 24/5 (or 4 4/5) from each side
-9/5 = b

Now we just fill in the correct variables (m and b) in the equation to have our final answer. 

y = 12/5x - 9/5
4 0
3 years ago
You earn $56 walking your neighbors dog for eight hours your friend Earns $36 painting your neighbors fence for four hours are t
KIM [24]
Yes i might be wrong but i think its yes
7 0
2 years ago
Miles bought a car that cost $23,556.to the nearest ten thousand,how much did the car cost
laila [671]
$20,000
In word form. he has twenty three thousand five hundred and fifty six, so we look to the digit next to the thousands, 3, and since its below 5, we keep 2 the same.
3 0
3 years ago
Part A
labwork [276]

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:

i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles

ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles

iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles

An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.

In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.

So that;

The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = \frac{3}{2}

  = 1.5

The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

            = 6

The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.

And,

5y = 5(1.5)

    = 7.5

The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

#SPJ1

5 0
2 years ago
If f(x) = g(x+1) and g(x) = x^2, find the value of f(3).
Elena-2011 [213]

\bf \begin{cases} f(x)=&g(x+1)\\ f(3)=&g(3+1)\\ &g(4)\\[-0.5em] \hrulefill& \hrulefill\\ g(x)=&x^2\\ g(4)=&4^2\\ &16 \end{cases}\qquad \qquad f(3)\implies g(4)\implies 16

8 0
3 years ago
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