Question

What is the simplified form of StartRoot StartFraction 2,160 x Superscript 8 Baseline Over 60 x squared EndFraction EndRoot? Assume

Answer 1

Answer:

Its B

Step-by-step explanation:

Answer 2

Answer:

$6x^3$

Step-by-step explanation:

We want to simplify $\sqrt{\frac{2,160x^8}{60x^2} }$

We can rewrite this using property of multiplication to obtain:

$\sqrt{\frac{2,160}{60}\times \frac{x^8}{x^2}}$

We simplify variable expression in the radicand using $\frac{a^m}{a^n}=a^{m-n}$

$\sqrt{36\times x^{8-2}}$

$\sqrt{36\times x^6}$

$\sqrt{36\times (x^{3})^2}$

$\sqrt{36}\times \sqrt{(x^{3})^2}$

$6\times x^{3}$

$6\times x^3$

Therefore the simplified form is

$6x^3$