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Doss [256]
2 years ago
8

A group of scientists have been sent on an expedition to test the soil in the Allegheny Mountains. They need to collect samples

from nine sites. The route for the expedition is shown in the image. The group starts at P and works its way around to Q, R, S, T, U, V, W, and X, in that order, before returning to P. What is the length of the route?
A.

50 units

B.

52 units

C.

55 units

D.

58 units

E.

60 units
Mathematics
2 answers:
3241004551 [841]2 years ago
9 0
It’s B. 52 units ...
enyata [817]2 years ago
4 0

Answer:

52

Step-by-step explanation:

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The coordinates of the midpoint of GH are M(8,0) and the coordinates of one endpoint are H(-2,9) The coordinates of the other en
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Answer:

work is attached and shown

4 0
3 years ago
Find the missing the side of the triangle. 19New A. 73‾√ in B. 72‾√ in C. 75‾√ in D. 77‾√ in
valina [46]

By applying Pythagorean's theorem, the missing side of this right-angled triangle is: A. 7√3 inches.

<h3>How to find the missing side?</h3>

By critically observing the triangle shown in the image attached below, we can logically deduce that it is a right-angled triangle. Thus, we would find the missing side by applying Pythagorean's theorem:

z² = x² + y²

Also, the sides of this right-angled triangle are:

  • Hypotenuse = 14 inches.
  • Opposite side = x inches.
  • Adjacent side = 7 inches.

Substituting the given parameters into the formula, we have;

14² = x² + 7²

196 = x² + 49

x² = 196 - 49

x² = 147

x = √147

x = √49 × √3

x = 7√3 inches.

Read more on Pythagorean theorem here: brainly.com/question/23200848

#SPJ1

3 0
1 year ago
Elasticity is also called
balandron [24]
Another word for elasticity is also called D: responsiveness
7 0
3 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
3 years ago
Did I do these two correctly?
natka813 [3]
Yes you did the equation on this page correctly.
7 0
3 years ago
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