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3 years ago

What is 14/48 in lowest terms

Mathematics

2 answers:

Marianna [84]3 years ago

3 0

Answer:

7/24

Step-by-step explanation:

14 ÷2 7

------------- = -------------

48 ÷2 24

enot [183]3 years ago

3 0

Answer:

7/24

Step-by-step explanation:

Divide both numbers by 2.

14/2=7

48=24

Lowest term, booooooooom

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What is the maximum height of of Anna's golf ball? The equation is y=x−0.04x2.

elena-s [515]

Given:

The height of a golf ball is represented by the equation:

$y=x-0.04x^2$

To find:

The maximum height of of Anna's golf ball.

Solution:

We have,

$y=x-0.04x^2$

Differentiate with respect to x.

$y'=1-0.04(2x)$

$y'=1-0.08x$

For critical values, $y'=0$ .

$1-0.08x=0$

$-0.08x=-1$

$x=\dfrac{-1}{-0.08}$

$x=12.5$

Differentiate y' with respect to x.

$y''=(0)-0.08(1)$

$y''=-0.08$

Since double derivative is negative, the function is maximum at $x=12.5$ .

Substitute $x=12.5$ in the given equation to get the maximum height.

$y=(12.5)-0.04(12.5)^2$

$y=12.5-0.04(156.25)$

$y=12.5-6.25$

$y=6.25$

Therefore, the maximum height of of Anna's golf ball is 6.25 units.

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3 years ago

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3 years ago

The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,

tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

$\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}$

Mean is represented by the following expression:

$\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}$ $\text{Mean}=\frac{84}{10}=8.4$

Population variance formula looks like this:

$\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}$

Then, substituting: