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emmainna [20.7K]
3 years ago
12

Help ASAP! With the slope of this

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

the slope is 4/1 so technically 4

the form y= mx+b may help

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5/6 of the students completed homework last night, but only 3/4 of those students did their work correctly. How many students di
Kisachek [45]

Answer:


Step-by-step explanation:

first your going to do the least common multiple which is 12 for both then your going to subtract because were trying to find out how many students did there work correctly. so, whatever you do to the denominator you do to the numerator so, its going to be 10/12 - 9/12= 1/12 is your answer.

8 0
3 years ago
Michael has 265 baseball cards. He wants to put them in packs of 9 cards each. How many cards will he have left over?
viktelen [127]
Michael will have 4 cards left because 265/9=29.4444444... then i do 29 (from the 29.4444) times 9 which gives me 261 and i did 265-261.
6 0
4 years ago
Find the surface area of the triangular prism.
sattari [20]
You have to work out the area of each side. The two identical triangles are 6x4=24 because 8/2 is 4. The base is 8x5=40. The back is 6x5=30 and the top is 10x5=50. You then add them all together to get 144 ft squared.
3 0
4 years ago
Read 2 more answers
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
4 years ago
3. Find the difference between the two expressions.<br> 1x - 5y)-1(x + 2y)
Fittoniya [83]

Answer:

-7y

Step-by-step explanation:

Our equation is:

\left(1x-5y\right)-1\left(x+2y\right)

First we dritribute

Now we have, x-5y-x-2y

Combine light terms

and we get -7y

5 0
3 years ago
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