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LuckyWell [14K]
3 years ago
6

Combine like terms y+4+3(y+2)

Mathematics
1 answer:
Archy [21]3 years ago
7 0
Y+4+3y+6
4y+10
Here the answer!
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HELP QUICK!!!!
Ann [662]

Answer:

<h2><u><em>rectangular prism  because it has 6 faces</em></u></h2>

cone dose not have a faces

triangular prism has 5 faces

5 0
3 years ago
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How do you find the surface area and volume of a cylinder ​
galina1969 [7]
<h2>Answer:</h2>

The surface area of a shape is the sum of the area of all of its faces. To find the area of a cylinder, you need to find the area of its bases and add that to the area of its outer wall. The formula for finding the area of a cylinder is A = 2πr2 + 2πrh.

<h2>Step-by-step explanation:</h2>
  • Surface area of a cylinder = 2πr 2 + 2πrh
  • Volume of a cylinder = πr 2 h
  • You need to know the radius and height to figure both the volume and surface area of a cylinder.
  • Answers for volume problems should always be in cubic units.
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5 0
2 years ago
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Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank's water are poured out. how many gallons of water are left in th
Advocard [28]

Answer:

Water left in tank is 3\frac{1}{6} gallons.

Step-by-step explanation:

Given :

Capacity of tank = 9.5 gallons  =\frac{95}{10}

Water taken out of tank =6\frac{1}{3}=\frac{19}{3} gallons

We have to find the water left in the tank.

Water left in the tank = Total capacity of tank - water taken out of tank

                                    =\frac{95}{10}-\frac{19}{3}

Taking LCM of (3,10)= 30

\Rightarrow \frac{95 \times 3-19 \times10}{30}

Solving further, we get,

\Rightarrow \frac{285-190}{30}

\Rightarrow \frac{95}{30}=\frac{19}{6}=3\frac{1}{6}

Thus, Water left in tank is 3\frac{1}{6} gallons..

5 0
3 years ago
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A certain brand of coffee costs $2.99 for 11.3 ounces. What is the unit rate? Enter your answer, rounded to the nearest cent, in
Marysya12 [62]
To find the unit rate, you would do 2.99 / 11.3 and get about 26 cents. So the unit rate would be 26 over 1 ( 26/1 ).


Hope I helped! 

Marsh
8 0
3 years ago
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Joe swam at the rate of 4.5 miles per hour. Joseph swam at the rate of 1/12 of a mile per minute. Who was swimming faster? By ho
kiruha [24]
Joseph was swimming faster because 1/12 of a mile per minute is around 5 miles per hour so Joseph was swimming 0.5 miles per hour faster than Joe.
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3 years ago
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