The discontinuity occurs at x = 0, since that is the only "problem" place in the graph that makes the function undefined. A vertical asymptote exists there. It is nonremoveable.
This function shows growth because the value that the base value of 6 is being multiplied by is 1.2. If the multiplication value is greater than 1, the function will grow. However, if it is less than 1, the function will decay.
Answer:
65°
Step-by-step explanation:
JM = JK (all sides of a rhombus are equal)
Angle JKM = 25° (isosceles triangle)
Angle JKL = 50° (consecutive angles of rhombus)
Angle MKL = 25° (angle subtraction)
Angle MLK = 130° (opposite angles of a rhombus)
Angle KLN = 50° (angles on a straight line)
Angle LKN = 40° (angle sum of triangle)
Angle MKN = 65° (angle addition)
Answer:
the negative and positive number line???? what exactly are you asking
Step-by-step explanation:
Answer: k=9/4
Step-by-step explanation: We can do this by finding a number that adds up to 3 when multiplied by 2. The best way to do this is to use ((b^2)/4) which can usually find you the number for a perfect square based on b, which we have. So, 3^2 / 4 =9/4, meaning k=9/4. We can check:
>x^2 +3x +9/4
> (x+3/2)(x+3/2)
Perfect square.
