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aleksandr82 [10.1K]
2 years ago
9

A prop assistant needs to rent a telescope to use for a scene in a movie. One company charges $57 per day plus a flat fee of $32

to rent a telescope. Another company charged $62 per day with no flat fee. For how many days would the total cost of renting a telescope be the same at both companies? Justify your answer by writing and solving an equation.
Fill in the blanks with the correct answers.

62x = 58x + 32, when x = ____. The total cost of renting a telescope would be the same at both companies for _____ day(s).
Mathematics
1 answer:
vovangra [49]2 years ago
5 0

The number of days for both Companies to have the same total amount is

6.4 days

<h3>Word Problem leading to Algebraic expression</h3>

 

Given Data

  • Let the total payment be y
  • Let the number of days be x

Company A

  • Charges per day = $57
  • Flat fee = $32

y = 57x+ 32 -----------------1

Company B

  • Charges per day = $62
  • Flat fee = $0

y = 62x + 0-----------------2

Equating 1 and 2 we have

57x+ 32 = 62x+ 0

Solving for x we have

62x-57x = 32

5x = 32

Divide both sides by 5

x = 32/5

x = 6.4 days

Learn more about word problem here:

brainly.com/question/13818690

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kozerog [31]

Answer:

The Customer Acquisition Cost for each customer in demographic group 1

The correct option is c

The Customer Acquisition Cost for Group 2

The  correct option is  b

Step-by-step explanation:

From the question we are told that

The marketing expenses per month for targeting the first group is E =  \$ 30,000

The marketing expenses per month for targeting the second group is F =  \$ 60,000

The number of customers for the demography of group 1 that will be attracted is N = 1000

The number of customers for the demography of group 2 that will be attracted is M = 1500

Generally the customer acquisition cost for group 1 is

K  =  \frac{E}{ N}

=>   K  =  \frac{30000}{ 1000}

=>   K  = \$ 30

Generally the customer acquisition cost for group 2 is

      Z  =  \frac{F}{ M}

=>   Z  =  \frac{60000}{ 1500}

=>   Z  = \$ 40  

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The exponential formula for this situtation will be given by:
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