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3 years ago

15

callista needs a carpet runner for her hallway. she needs it to be 1 1/2 feet wide and 4 feet long. what is the area of the carp

et runner callista needs?

2 answers:

nadya68 [22]3 years ago

5 0

Answer:

Area = 6

Step-by-step explanation:

1/2 is the same as 0.5 feet.

To find the area you have to times the length by the width.

4 feet x 1.5 feet =6

Soloha48 [4]3 years ago

3 0

Answer:

Area=6

Step-by-step explanation:

1/2 is the same as 0.5 feet.

To find the area you have to times the length by the width.

4 feet x 1.5 feet =6

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Answer:

Hi there!

Your answer is:

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Step-by-step explanation:

The distance formula is

√ ( (x2-x1)^2 + (y2-y1)^2 )

In your points:

A (-3, -2)

-3 is x1

-2 is y1

B (4, -7)

4 is x2

-7 is y2

Plug in to distance formula

√ ( 4-( -3))^2 + ( -7 - (-2))^2

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√ 49 + 25

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This equals roughly 8.6 units!

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3 years ago

What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?

tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

so

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

$x=\frac{8\pm\sqrt{4}} {2}$

$x=\frac{8\pm2} {2}$

$x=\frac{8+2} {2}=5$

$x=\frac{8-2} {2}=3$

so

x=3, x=5

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Answer:

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