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solniwko [45]
3 years ago
14

Simplify 2n - 7+3(4n-3) A.14n-16 B. -14n+12 C.-14n-13 D.14n-10

Mathematics
1 answer:
Hoochie [10]3 years ago
6 0
<span>Simplifying 2n + -7 + 3(4n + -3) = 0 Reorder the terms: 2n + -7 + 3(-3 + 4n) = 0 2n + -7 + (-3 * 3 + 4n * 3) = 0 2n + -7 + (-9 + 12n) = 0 Reorder the terms: -7 + -9 + 2n + 12n = 0 Combine like terms: -7 + -9 = -16 -16 + 2n + 12n = 0 Combine like terms: 2n + 12n = 14n -16 + 14n = 0 Solving -16 + 14n = 0 Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + 14n = 0 + 16 Combine like terms: -16 + 16 = 0 0 + 14n = 0 + 16 14n = 0 + 16 Combine like terms: 0 + 16 = 16 14n = 16 Divide each side by '14'. n = 1.142857143 Simplifying n = 1.142857143</span>
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Ian picked 5 times as many berries as Michelle.Joe picked 7 times as many berries Michelle.Together they picked 208 berries.How
Rasek [7]
Michelle: x
Ian: 5x
Joe: 7x
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3 years ago
The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

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