Ask question

Ask question

All categories

3 years ago

14

Simplify 2n - 7+3(4n-3) A.14n-16 B. -14n+12 C.-14n-13 D.14n-10

1 answer:

Hoochie [10]3 years ago

6 0

<span>Simplifying 2n + -7 + 3(4n + -3) = 0 Reorder the terms: 2n + -7 + 3(-3 + 4n) = 0 2n + -7 + (-3 * 3 + 4n * 3) = 0 2n + -7 + (-9 + 12n) = 0 Reorder the terms: -7 + -9 + 2n + 12n = 0 Combine like terms: -7 + -9 = -16 -16 + 2n + 12n = 0 Combine like terms: 2n + 12n = 14n -16 + 14n = 0 Solving -16 + 14n = 0 Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + 14n = 0 + 16 Combine like terms: -16 + 16 = 0 0 + 14n = 0 + 16 14n = 0 + 16 Combine like terms: 0 + 16 = 16 14n = 16 Divide each side by '14'. n = 1.142857143 Simplifying n = 1.142857143</span>

You might be interested in

7.63 repeating as a fraction

Katyanochek1 [597]

Answer:

763/100 is the answer to this

3 0

3 years ago

-15=2t-11 does any one know it please

Murljashka [212]

Add 11 to both sides:

-4=-2t

divide 2 by both sides

2=t

Hope it helps! Comment if you have any questions!

5 0

3 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

The perimeter of the rectangle is 30 centimeters.What is the side of c

Dafna1 [17]

Answer:

Step-by-step explanation:

Emmm

8 0

4 years ago

Read 2 more answers

Whats the answer and work for 7x+8(x+1/4)=3(6x-9)-8 ?

Marat540 [252]

Answer:

=37

_

3

Step-by-step explanation:

3 0

3 years ago